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In Young's double slit experiment, the 1...

In Young's double slit experiment, the 10th maximum of wavelength `lambda_(1)` is at distance of `y_(1)` from the central maximum. When the wavelength of the source is changed to `lambda_(2)` , 5th maximum is at a distance of `y_(2)` from its central masximum. Then `(y_(1))/(y_(2))` is

A

`(2lambda_(1))/lambda_(2)`

B

`(2lambda_(2))/lambda_(1)`

C

`lambda_(1)/(2lambda_(2))`

D

`lambda_(2)/(2lambda_(1))`

Text Solution

Verified by Experts

The correct Answer is:
A

We have `y_(1)=10omega_(1)=(10lambda_(1)D)/d, y_(2)=5 omega_(2)=(5lambda_(2)D)/d`
`:. y_(1)/y_(2)=(2lambda_(1))/lambda_(2)`
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