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Two beams of ligth having intensities I and 4I interface to produce a fringe pattern on a screen. The phase difference between the beams is `(pi)/(2)` at point A and `pi` at point B. Then the difference between the resultant intensities at A and B is

A

`2I`

B

`4I`

C

`5I`

D

`7I`

Text Solution

Verified by Experts

The correct Answer is:
B

Resultant intensity `I_(R)=I_(1)+I_(2)+2sqrt(I_(1)I_(2))cosphi`
`I_(A)=5I and I_(B)=I`
`:.` The difference between the intensity `I_(A)-I_(B)=4I`
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