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In a Young's experiment, one of the slit...

In a Young's experiment, one of the slits is covered with a transparent sheet of thickness `3.6xx10^(-3)cm` due to which position of central fringe shifts to a position originally occupied by 30th fringe. If `lambda=6000 Å`, then find the refractive index of the sheet.

A

`1.5`

B

`1.2`

C

`1.4`

D

`1.6`

Text Solution

Verified by Experts

The correct Answer is:
A
Number of fringes shifted `N=((mu-1)t)/lambda`
`:.` Refractive index of the sheet,
`mu=(Nlambda)/t+1=(30xx6000xx10^(-10))/(3.6xx10^(-5))+1=1.5`
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