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Light of wavelength lambda is incident o...

Light of wavelength `lambda` is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will be equal if D is ––

A

`(2lambda^(2))/d`

B

`d^(2)/(2lambda)`

C

`d/lambda`

D

`(2lambda)/d`

Text Solution

Verified by Experts

The correct Answer is:
B
In diffraction fringe width `beta=(lambdaD)/d`
when `d/2=beta" then"d/2=(lambdaD)/drArrD=d^(2)/(2lambda)`
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