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If two slits is Young's experiment are 0...

If two slits is Young's experiment are `0.4` mm apart and fringe width on a screen 200 cm away is 2 mm the wavelength of light illuminating the slits is

A

500 mm

B

600 mm

C

400 mm

D

300 mm

Text Solution

Verified by Experts

The correct Answer is:
C
Fringe width `beta=(Dlambda)/d`
Given `d=0.4mm = 0.04 cm D=200 cm`
`beta=2mm=0.2cm`
`:.0.2=(200xxlambda)/(0.04)rArrlambda=400nm`
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