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An interference pattern is observed by Y...

An interference pattern is observed by Young's double slit experiment.If now the separation between coherent source is halved and the distance of screen from coheren sources is doubled, then now fringe width

A

becomes double

B

becomes ne-fourth

C

remains same

D

becomes four times

Text Solution

Verified by Experts

The correct Answer is:
D

Frime width `(W) =q(Dlambda)/(d)`
Now, distance between the coherent souces is halved i.e `d'=d//2` and distance of coherent source and screen is doubled i.e `D'=2D`
`therefore " "W'=(D'lambda)/(d)=(2Dlambda)/(d//2)=(4Dlambda)/(d)rArr(W')/(w)=4`
`rArr W'=4W`(becomes four times)
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Knowledge Check

  • In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :

    A
    Half
    B
    Four times
    C
    One-fourth
    D
    Double
  • The fringe pattern observed on Young's double-slit experiment is

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    a diffraction pattern
    B
    an interference pattern
    C
    a combination of diffraction and interference pattern
    D
    neither a diffraction nor an interference pattern
  • In Young's double slite experiment, the separation between the two slite is halved. The fringe width

    A
    remains same
    B
    becomes double
    C
    reduced of half
    D
    becomes `(1//4)^(th)` of its earilier value
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