A simple telescope, consisting of an objective of focal length 60 cm and a single eye lens of focal length 5 cm is focussed on a distant object in such a way that parallel rays comes out from the eye lens. If the object subtends an angle `2^(@)` at the objective, the angular width of the image

Options

A. `10^(2)`
B. `24^(2)`
C. `50^(2)`
D. `(1^(@))/(6)`

Answer

B

Explanation

For telescope
It is a case of normal adjustment
Hence, `M =(F_(0))/(F_(e))also M =beta//alpha`
`Therefore ,(beta)/(alpha)=(f_(0))/(f_(e))`
Here `F_(0)=60 cm F_(e)=5cmrArralpha=2^(@)`
Hence, `beta=24^(@)`