A Specimen of silicon is to be made P-type semiconductor for this one atom of lindium, on an average, is doped in `5xx10^(22) atom//m^(3)` then the number of acceptor atoms per `cm^(3)` will be

Options

A. `2.5xx10^(30)`
B. `1.0xx10^(13)`
C. `1.0xx10^(15)`
D. `2.5xx10^(36)`

Answer

C

Explanation

Given for one indium atom to be doped in `5xx10^(7)` silicon atoms
Number density of silicon `=5xx10^(22)`
Number acceptor `atom//cm^(3)=(5xx10^(22))/(5xx10^(7))=1xx10^(15) cm^(-3)` Hence number of acceptor `atom//cm^(3)` is `1xx10^(15) cm^(-3)`