The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is

Options

A. `2:-1`
B. `1:1`
C. `1:1`
D. `1:-2`

Answer

B

Explanation

Kinetic energy of an electron in a Bohr orbit of a hydrogen atom is given as
`KE_(n) = (Rhc)/(n^(2))`
Total energy of an electron in a Bohr orbit of a hydrogen atom is given as
`TE_(n) = (-Rhc)/(n^(2)`………..(ii)
Dividing Eq. (i) by Eq. (ii), we get
`(KE_(n))/(TE_(n))=((Rhc)/n^(2))/((RhC)/n^(2))rArr KE_(n):TE_(n)=1:-1`