If a capacitor having capacittance 2F and plate separation of 0.5 cm will have area

Options

A. `1130cm^(2)`
B. `1130m^(2)`
C. `1130 km^(2)`
D. none of these

Answer

C

Explanation

`therefore` Capacitance of a parallel plate capacitor, `C=(epsilon_(0)A)/dA=(Cd)/epsilon_(0)=(2 xx 0.5 xx 10^(-2))/(8.85 xx 10^(-12))`
`=1.130 xx 10^(9)m^(2)` = 1130 `km^(2)`