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The equation of the circle of radius 5 i...

The equation of the circle of radius 5 in the first quadrant which touches the x-axis and the line `3x-4y=0` is `x^2+y^2-24 x-y-25=0` `x^2+y^2-30 x-10 y+225=0` `x^2+y^2-16 x-18 y-64=0` `x^2+y^2-20 x-12 y+144=0`

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The equation of the circle of radius 5 in the first quadrant which touches the x-axis and the line 3x-4y=0 is x^(2)+y^(2)-24x-y-25=0x^(2)+y^(2)-30x-10y+225=0x^(2)+y^(2)-16x-18y-64=0x^(2)+y^(2)-20x-12y+144=0

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