A ball is projecte with a velocity `20 ms^-1` at an angle to the horizontal. In order to have the maximum range. Its velocity at the highest position must be

A body is projected with a speed (u) at an angle to the horizontal to have maximum range. What is its velocity at the highest point ?

A body is projected with a speed (u) at an angle to the horizontal to have maximum range. What is its velocity at the highest point ?

A body is projected with speed u at an angle theta to the horizontal to have maximum range. Its velocity at the highest point will be ___.

A body is projected with a speed v at an angle theta with horizontal to have maximum range. What is the velocity at the highest’ point?

A ball of mass m is projected with a velocity 'u' at angle theta with the horizontal. It collides with a smooth box of mass 'M' at its highest position. If the co-efficient of restitution is 'e' . FInd the velocity of the ball after collision

A ball of mass m is projected with a velocity 'u' at angle theta with the horizontal. It collides with a smooth box of mass 'M' at its highest position. If the co-efficient of restitution is 'e' . Find the horizontal distance travelled by the ball before collision.

A boy throws a ball of mass 200g with a velocity 20ms^-1 at an angle of 40° with the horizontal. What is the kinetic energy of the ball at the highest point of the trajectory?

A body is projected with velocity u so that its horizontal range is twice the maximum height.The range is

A ball is projected with a velocity 20 sqrt(3) ms^(-1) at angle 60^(@) to the horizontal. The time interval after which the velocity vector will make an angle 30^(@) to the horizontal is (Take, g = 10 ms^(-2))

A ball is projected with a velocity 20 sqrt(3) ms^(-1) at angle 60^(@) to the horizontal. The time interval after which the velocity vector will make an angle 30^(@) to the horizontal is (Take, g = 10 ms^(-2))