The difference rate law for the reaction
`H_(2) +I_(2) to 2HI` is

The differential rate law for the reaction H_2 + I_2 rarr 2HI is

For the reaction 2HI hArr H_(2)+I_(2)

For the reaction , 2HI hArr H_(2) + I_(2)

On a given condition, the equilibrium concentration of HI , H_(2) and I_(2) are 0.80 , 0.10 and 0.10 mole/litre. The equilibrium constant for the reaction H_(2) + I_(2) hArr 2HI will be

The rate of the reaction H_2 + I_2 to 2HI " is given by" :^(**"**) Rate = 1*7 xx 10^(-19) [H_2][I_2] " at " 25^@C The rate of decomposition of gaseous 2HI to H_2 and I_2 is given by : Rate = 2*4 xx 10^(-21) [H_2][I_2] " at " 25^@C . Calculate the equilibrium constant for the formation of HI from H_2 and I_2 " at " 25^@C .