Find the equation of the plane through the line of intersection of the planes `x" "+" "y" "+" "z" "=" "1` and `2x" "+" "3y" "+" "4z" "=" "5` which is perpendicular to the plane`x" "" "y" "+" "z" "=" "0` .

Find the equation of the plane through the line of intersection of the planes given by the equations x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane given by the equation x - y + z = 0.

Find the equation of the plane through the line of intersection of the planes given by the equations x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane given by the equation x - y + z = 0.

The equation of the plane passing through the line of intersection of the planes x + y + 2z = 1,2x + 3y + 4z = 7, and perpendicular to the plane x - 5y + 3z = 5 is given by:

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to x-y+z=0

Find the equation of the plane passing through the line of intersection of the planes .x+ y+ z = 6 and 2x+ 3y+ 4z-5 = 0 and the point (1,1,1).

Find the equation of the plane through the line of intersection of the planes given by the equations x + 2y + 3z = 4 and 2x + y - z = -5 which is perpendicular to the plane given by the equation 5x + 3y + 6z = -8.

The equation of the plane through the line of intersection of the planes x + y + z - 6 = 0, 2x + 3y + 4z +5 = 0 and the point (1,1,1) is

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and which is perpendicular to the plane x-y+z=0

Find the equation of the plane through the line of intersection of the planes given by the.equations 2x + 3y - z = - 1 and x + y- 2z = - 3 which is perpendicular to the plane given by the equation 3x-y-2z= 4.