Statement 1: `1^(99)+2^(99)++100^(99)` is divisible by 10100. Statement 2: `a^n+b^n` is divisible by `a+bifn` is odd.

Statement-1: 7^(n)-3^(n) is divisible by 4. Statement-2: 7^(n)=(4+3)^(n) .

Statement-1: 2^(33)-1 is divisible by 7. Statement-2: x^(n)-a^(n) is divisibel by x-a, for all n in N and x ne a .

Statement 1:3^(2n+2)-8n-9 is divisible by 64,AA n in N. Statement 2:(1+x)^(n)-nx-1 is divisible by x^(2),AA n in N

Prove that 13^99-19^93 is divisible by 162.

Statement-1: For each natural number n,(n+1)^(7)-n^(7)-1 is divisible by 7 . Statement-2: For each natural number n,n^(7)-n is divisible by 7 .

If (x^(100)+2x^(99)+k) is divisible by ( x+1 ) then the value of k is

Find the remainder when 7^(99) is divisible by 2400.

Statement -1 For each natural number n,(n+1)^(7)-n^7-1 is divisible by 7. Statement -2 For each natural number n,n^7-n is divisible by 7.

If 24AB4 is divisible by 99, then A xx B is :

Test whether 382546692 is divisible by 99 or not.