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If t(1) be the time taken by a body to c...

If `t_(1)` be the time taken by a body to clear the top of a building and `t_(2)` be the time spent in air, then `t_(2):t_(1)` will be -

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A tank full of water has a small hole at its bottom. Let t_(1) be the time taken to empty first one third of the tank and t_(2) be the time taken to empty second one third of the tank and t_(3) be the time taken to empty rest of the tank then (a). t_(1)=t_(2)=t_(3) (b). t_(1)gtt_(2)gtt_(3) (c). t_(1)ltt_(2)ltt_(3) (d). t_(1)gtt_(2)ltt_(3)

A tank full of water has a small hole at its bottom. Let t_(1) be the time taken to empty first one third of the tank and t_(2) be the time taken to empty second one third of the tank and t_(3) be the time taken to empty rest of the tank then (a). t_(1)=t_(2)=t_(3) (b). t_(1)gtt_(2)gtt_(3) (c). t_(1)ltt_(2)ltt_(3) (d). t_(1)gtt_(2)ltt_(3)

A tank full of water has a small hole at its bottom. Let t_(1) be the time taken to empty first one third of the tank and t_(2) be the time taken to empty second one third of the tank and t_(3) be the time taken to empty rest of the tank then (a). t_(1)=t_(2)=t_(3) (b). t_(1)gtt_(2)gtt_(3) (c). t_(1)ltt_(2)ltt_(3) (d). t_(1)gtt_(2)ltt_(3)

A tank is filled with a liquid upto a height H, A small hole is made at the bottom of this tank Let t_(1) be the time taken to empty first half of the tank and t_(2) time taken to empty rest half of the tank then find (t_(1))/(t_(2))

A tank is filled with a liquid upto a height H, A small hole is made at the bottom of this tank Let t_(1) be the time taken to empty first half of the tank and t_(2) time taken to empty rest half of the tank then find (t_(1))/(t_(2))

A tank is filled with a liquid upto a height H, A small hole is made at the bottom of this tank Let t_(1) be the time taken to empty first half of the tank and t_(2) time taken to empty rest half of the tank then find (t_(1))/(t_(2))

A tank is filled with a liquid upto a height H, A small hole is made at the bottom of this tank Let t_(1) be the time taken to empty first half of the tank and t_(2) time taken to empty rest half of the tank then find (t_(1))/(t_(2))

A particle executes SHM in accordance with x=A"sin"omegat . If t_(1) is the time taken by it to reach from x=0 to x=sqrt(3)(A//2) and t_(2) is the time taken by it to reach from x=sqrt(3)//2 A to x=A , the value of t_(1)//t_(2) is

A particle executes SHM in accordance with x=A"sin"omegat . If t_(1) is the time taken by it to reach from x=0 to x=sqrt(3)(A//2) and t_(2) is the time taken by it to reach from x=sqrt(3)//2 A to x=A , the value of t_(1)//t_(2) is