In the following circuit, resistance of potentiometer wire is `100 Omega`. Power consumption in potentiometer wire is same when jockey is placed at 10 cm from end A or end B. Internal resistance of cell (r ) is

In the circuit shown, a four-wire potentiometer is made of a 400 cm long wire, which extents between A and B . The resistance per unit length of the potentiometer wire is r/L=0.01 Omega//cm. If an ideal voltmeter is connected as shown with jockey J at 50 cm from end A, the expected reading of the voltmeter will be :

The terminals of a cell are cnnected to resistance R and the falll of potential across R is balaced against the fall of potential on a potentiometer wire.When R is 20 Omega and 10 Omega respectively, the corresponding lengths of potentiometer wire are 1.5 m and 1.2 m Claculate the internal resistance of the cell

In the circuit shown, a four-wire potentiometer is made of a 400 cm long wire, which extends between A and B. The resistance per unit length of the potentiometer wire is r = 0.01 Omega //cm . If an ideal voltmeter is connected as shown with jockey J at 50 cm from end A, the expecteed reading of the voltmeter will be _______ volts.

In a potentiometer experiment, the galvanometer shows no deflection when a cell is connected across 60 cm of the potentiometer wire. If the cell is shunted by a resistance of 6 Omega , the balance is obtained across 50 cm of the wire. The internal resistance of the cell is

In a potentiometer experiment, the galvanometer shows no deflection when a cell is connected across 60 cm of the potentiometer wire. If the cell is shunted by a resistance of 6 Omega , the balance is obtained across 50 cm of the wire. The internal resistance of the cell is

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.

In a potentiometer experiment, it is found that no current passes through the galvanometer when the terminals of the cell are connected across 52 cm of the potentiometer wire. If the cell is shunted by a resistance of 5 Omega the balance point is found at 40 cm of the wire from the same end. The internal resistance of the cell is