0.80g of impure `(NH_(4))_(2) SO_(4)` was boiled with 100mL of a 0.2N NaOH solution was neutralized using 5mL of a `0.2N H_(2)SO_(4)` solution. The percentage purity of the `(NH_(4))_(2)SO_(4)` sample is:

0.80g of impure (NH_(4))_(2) SO_(4) was boiled with 100mL of a 0.2N NaOH solution till all the NH_3 (g) evolved. the remaining solution was diluted to 250 mL . 25 mL of this solution was neutralized using 5mL of a 0.2N H_(2)SO_(4) solution. The percentage purity of the (NH_(4))_(2)SO_(4) sample is:

0.7g of (NH_(4))_(2)SO_(4) sample was boiled with 100mL of 0.2 N NaOH solution was diluted to 250 ml. 25mL of this solution was neutralised using 10mL of a 0.1 N H_(2)SO_(4) solution. The percentage purity of the (NH_(4))_(2)SO_(4) sample is :

0.7g of (NH_(4))_(2)SO_(4) sample was boiled with 100mL of 0.2 N NaOH solution was diluted to 250 ml. 25mL of this solution was neutralised using 10mL of a 0.1 N H_(2)SO_(4) solution. The percentage purity of the (NH_(4))_(2)SO_(4) sample is :

0.70g mixture of (NH_(4))_(2)SO_(4) was boiled with 100 ml of 0.2 N NaOH solution will all the NH_(3)(g) evolved and get dissolved to 250 mL and 10 mL of this solution was neutralised by using 10 mL of a 0.1 N H_(2)SO_(4) . The percentage purity of the (NH_(4))SO_(4) was boiled with 100 ml of 0.2 N NaOH solution till all the NH_(3)(g) evolved and get dissolved to 250 mL and 10 mL of this solution was neutralised by using 10 mL of a 0.1 N H_(2)SO_(4) solution. the percentage purity of the (NH_(4))_(2)SO_(4) sample is-

0.80g is impure (NH_4)SO_4) was boiled with 100mL of 0.2N NaOH solution till all the NH_3 (g) evolved. The remaining solution was diluted to 250mL. 25mL of this solution was neutralized using 5mL of 0.2 NH_2 SO_4 solution. The percentage purity of the (NH_4)_2SO_4 sample is :

0.80g is impure (NH_4)SO_4) was boiled with 100mL of 0.2N NaOH solution till all the NH_3 (g) evolved. The remaining solution was diluted to 250mL. 25mL of this solution was neutralized using 5mL of 0.2 NH_2 SO_4 solution. The percentage purity of the (NH_4)_2SO_4 sample is :

Find the volume (in mL) of 0.2 (N) NaOH solution required to neutralise 25 mL of 0.2(N) H_(2)SO_(4) solution.

100mL of " 0.1 M NaOH" solution is titrated with 100mL of "0.5 M "H_(2)SO_(4) solution. The pH of the resulting solution is : ( For H_(2)SO_(4), K_(a1)=10^(-2))

100mL of " 0.1 M NaOH" solution is titrated with 100mL of "0.5 M "H_(2)SO_(4) solution. The pH of the resulting solution is : ( For H_(2)SO_(4), K_(a1)=10^(-2))

If 100 mL of 1 N H_(2)SO_(4) is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be