The `NH_(3)` evolved due to complete conversion of N from 1.12g sample of protein was absorbed in `45 "ml of" 0.4N HNO_(3)`. The excess acid required `20 "ml of" 0.1N NaOH`. The % N in the sampl is:

The NH_3 evolved due to complete conversion of N from 1.12g sample of protien was absorbed in 45mL of 0.4 NHNO_3 . The excess acid required 20mL of 0.1NNaOH . The % N in the sample is :

The NH_3 evolved due to complete conversion of N from 1.12g sample of protien was absorbed in 45mL of 0.4 NHO_3 . The excess acid required 20mL of 1.0NaOH . The % N in the sample is :

The NH_(3) evolved from 2.8 gm sample of protein was absorbed in 45 ml of 0.2 M HNO_(3) . The excess acid required 20 ml of 0.05 M NaOH % of N in the sample will be :

A 10.0 ml of (NH_(4))_(2) SO_(4) solution was treated with excess of NaOH . The ammonia evolved was absorbed in 50 ml of 0.1 N HCl. The excess HCl required 20 ml of 0.1 N. NaOH . Calculate the strength of (NH_(4))_(2) SO_(4) in the solution.

0.303 g of an organic compound was analysed for nitrogen by Kjeldahl's method. The ammonia evolved was absorbed in 50 ml of 0.1 N H_2 SO_4 . The excess acid required 25 ml of 0.1 N NaOH for neutralisation. Calculate the percentage of nitrogen in the compound.

The neutralization of 50 ml of 0.25 NH_2SO_4 will require ____ ml of 0.50 N NaOH.