Find the sum `3/(1xx2)xx1/2+4/(2xx3)xx(1/2)^2+5/(3xx4)xx(1/2)^2+ ton` terms.

Find the sum of the series: (1xx2xx4)+(2xx3xx7)+(3xx4xx10)+... "to n terms"

Find the sum of the series (2)/(1xx2)+(5)/(2xx3)xx2+(10)/(3xx4)xx2^(2)+(17)/(4xx5)xx2^(3)+rarr terms.

[(1)/(1xx2)+(1)/(2xx3)+(1)/(3xx4)+,+(1)/(99xx100)]=

Find the sum (1xx2)/(3!)+(2xx2)^2/(4!)+(3xx2)^3/(5!)+....+(20xx2)^30/(22!)

1 (4)/(5) xx 2 (2)/(3) xx 3 (1)/(3) xx (1)/(4) =

Find the sum to n terms of the series: (1)/(1xx2)+(1)/(2xx3)+(1)/(3xx4)+

Find the sum of the series: 1xx2^(2)+3xx3^(2)+5xx4^(2)+... "to n terms"

Find the sum of the series: 1xx2^(2)+2xx3^(2)+3xx4^(2)+... "to n terms"

If A= 1/(1xx2)+1/(1xx4)+1/(2xx3)+1/(4xx7)+ 1/(3xx4)+1/(7xx10) ...... upto 20 terms, then what is the value of A? यदि 1/(1xx2)+1/(1xx4)+1/(2xx3)+1/(4xx7)+ 1/(3xx4)+1/(7xx10).....20 पदों तक हो, तो A का मान क्या है?