Let `x=1+3a+6a^2+10 a^3+ ,|a|<1.` `y=1+4b+10 b^2+20 b^3+ ,|b|<1.` Find `S+1+3(a b)+5(a b)^2+` in terms of `xa n dydot`

If y=3 x + 6 x^(2) + 10 x^(3) +… then x =

Let f(x)=x^3-6x^2+12x-3 . Then at x=2 f(x) has

Let f (x) =3x ^(10) -7x ^(8) +5x^(6) -21 x ^(3) +3x ^(2) -7 265 (lim _(htoo) (h ^(4) +3h^(2))/((f(1-h) -f (1))sin5h))=

Let S_1 = 4+6/3+8/3^2+10/3^3+...+oo and S_2 =sum_(n=1)^oo 1/((3n+1)(3n+4)), then the value of the S_1/(10 S_2) is

Let f(x) = x^(3) - 6x^(2) + 15x + 3 . Then

Let f(x) = 2 + 2x -3x^(2//3) " on " [-1, 10//3] . Then f has

Let f (x) =x ^(3) + 6x ^(2) + ax +2, if (-3, -1) is the largest possible interval for which f (x) is decreasing function, then a=

Let X={1,2,3, , 10},A={1,2,3,4,5},B={1,3,5,7,9}a n dC={2,4,8, 10} , verify the following A-B=AnnB^c

The fraction equivalent to 1 2/3 is (a) (10)/3 (b) 3/5 (c) (10)/6 (d) 6/(10)