The rate constant is doubled when temperature increases from `27^(@)C` to `37^(@)C`. Activation energy in kJ is

The rate of reaction is doubled when the temperature changes from 27^@C to 37^@C . Calculate the energy of activation.

The rate of particular reaction doubles when temperature changes from 27^(@)C to 37^(@)C. Calculate the energy of activation of such a reaction.

If the rate of a reaction gets doubled as the temperature is increased from 27^@ " to " 37^@C . Find the activation energy of reaction?

If the rate of a reaction gets doubled as the temperature is increased from 27^@ " to " 37^@C . Find the activation energy of reaction?

The rate of a reaction gets doubled when temperature increase by 27^(@) C "to" 37^(@) . By what factor will it change for the temperature range 17^(@) C to 27^(@) C

The rate of a reaction gets doubled when temperature increase by 27^(@) C "to" 37^(@) . By what factor will it change for the temperature range 17^(@) C to 27^(@) C