The system of equation `kx+y+z=1, x +ky+z=k and x+y+kz=k^(2)` has no solution if k equals

For what value of 'K', the system of equations kx+y+z=1, x+ky+z=k" and "x+y+kz=K^(2) has no solution ?

The system of equations kx + y + z =1, x + ky + z = k and x + y + zk = k^(2) has no solution if k is equal to :

Let the following system of equations {:(kx+y+z=1),(x+ky+z=k),(x+y+kz=k^2):} has no solution . Find |k|.

Let the following system of equations {:(kx+y+z=1),(x+ky+z=k),(x+y+kz=k^2):} has no solution . Find |k|.

If the system of equations x+y+z=6, x+2y+kz=0 and x+2y+3z=10 has no solution, then the value of k is -

The system of linear equations kx + y + z = 1, x + ky + z = 1 and x + y + kz = 1 has a unique solution under which one of the following conditions ?

The number of integral value(s) of k such that the system of equations kz-2y-z=x, ky-z=z+3x and 2x+kz=2y-z has non - trivial solution, is/are

The number of integral value(s) of k such that the system of equations kz-2y-z=x, ky-z=z+3x and 2x+kz=2y-z has non - trivial solution, is/are