Find the dimensions of the prayer hall discussed in Section 4.1.

Explanation

Let the breadth be `x` and the length be `(2x + 1)m`

Given that the area of the hall is `300 m^2`
The hall is in a rectangular shape.
Area of the hall = length × breadth
`300 m^2 = x × (2x+ 1)`
`2x^2 + x - 300 = 0`
Split bx into such a way that it is equal to a×c
1x can be split into - 24 and 25. [ ∵ (- 24) × (25) = - 600]

`2x^2 + x - 300 = 0` can be written as
`2x^2 - 24x + 25x - 300 = 0`
Take out common terms. `2x (x - 12) + 25 (x - 12) = 0`
`(x - 12)(2x + 25) = 0`
Since the roots of the given equation are `x = 12 or x = - 12.5`
The breadth of the hall cannot be negative.
`x = 12` is the breadth of the hall and the length = `2x + 1 = 25 m`