Calculate the mean and variance from the data given below:

Explanation

`barX=A+(sumfd')/(sumf)xxC`
`=25+(0)/(27)xx10`
=25
`"Variance"(sigma^(2))=[(sumfd'^(2))/(N)-((sumfd')/(N))^(2)]xxC^(2)`
`=[(32)/(27)-((0)/(27))^(2)]xx10^(2)`
`implies " " sigma^(2)=1.185xx100`
=118.51
Mean =25, Variance`(sigma^(2))`=118.51.