Home
Class 11
PHYSICS
The percentage error in determination fo...

The percentage error in determination fo `g= 4pi^2(I)/(t^2),` when I and t are measured with `+- 1%` and `+- 2%` errors is

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate percentage error in the determination of g = 4pi^2 I//t^2, when I and t are measured with +- 2% and +- 3% errors respectively.

Calculate the percentage of error in the determination of g=4pi^2l//_t2 when l and t are measured with _-^+2% and _-^+3% errors respectively.

Calculate percentage error in determination of time period of a pendulum. T = 2pi (sqrt(l))/(g) where, l and g are measured with +-1% and +-2% .

Calculate percentage error in determination of time period of a pendulum. T = 2pi (sqrt(l))/(g) where, l and g are measured with +-1% and +-2% .

The resistance R of a wire is found by determining its length l and radius r. The percentage errors in measurement of l and r are respectively 1% and 2%. The percentage error in measurement of R is

The percentage error in measurements of length and time period is 2% and 1% respectively . The percentage error in measurements of 'g' is