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In the adjoining figure, BD = CE and ang...

In the adjoining figure, BD = CE and `angleADB=angleAEC=90^(@)`, prove that
(i) `DeltaABD cong DeltaACE` (ii) ABC is an isosceles triangle.

Text Solution

Verified by Experts

(i) In `DeltaABD` and `DeltaACE`,
`:' {(angle3=angle3,"(common)"),(angle1=angle2,"(each "90^(@)", given)"),(BD=CE,"(given)"):}`
`:. DeltaABD cong DeltaACE` (AAS) Hence Proved.
(ii) `AB = AC` (c.p.c.t)
Hence, `DeltaABC` is an isosceles triangle. Hence Proved.
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