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In the given figure, D and E are the poi...

In the given figure, D and E are the points on the base BC of `DeltaABC` such that `BD=CE, AD= AE` and `angleADE=angleAED`, prove that `DeltaADB cong DeltaAEC`.

Text Solution

Verified by Experts

Since `angle1=angle2` (given)
`implies" "180-angle3=180-angle4` (L.P.A.)
`implies" "angle3=angle4`
Now, in `DeltaADB` and `DeltaAEC`,
`:' {(BD=CE,"(given)"),(angle3=angle4,"(proved above)"),(AD=AE,"(given)"):}`
`:. DeltaADB cong DeltaAEC` (SAS) Hence Proved.
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