In the adjoining figure, `AD = DC` and bisects `angleADC`. Prove that `DeltaADB cong DeltaCDB`.

In the adjoining figure, BD = CE and angleADB=angleAEC=90^(@) , prove that (i) DeltaABD cong DeltaACE (ii) ABC is an isosceles triangle.

In the adjoining figure, AB = CD and AB||CD prove that (i) DeltaAOB cong DeltaDOC (ii) AD and BC bisect each other at the point O.

In the adjoining figure AB = CD and AB"||"CD prove that : (i) DeltaAOB cong DeltaDOG (ii) AD and BC bisect each other at point O.

In the given figure , AC gt AB and AD bisects angle BAC Prove that angle ADC gt ADB

In the adjoining figure, angleBAC=angleBDC and angleABC=angleBCD . Prove that : (i) DeltaABC cong DeltaDCB (ii) DeltaABE cong DeltaDCF .

Given AD=DC and DB biscets angleADC . (i) Prove that, DeltaADB cong DeltaCDB (ii) If angleABD=48^(@) , find angleCBD .

In the given figure, AB = AD and angle1=angle2 . Prove that : BC = DC

In the adjoining figure, BD = DC and AE = ED. Prove that area of Delta ACE = (1)/(4) " area of " Delta ABC

In the adjoining figure, AB=AC and BD=DC Prove that Delta ADB-=Delta ADC and hence show that (i) /_ADB-=/_ADC=90^(@) , (ii) /_BAD=/_CAD

In the given figure, AB = CD and AD = CB. Prove that DeltaABD~=DeltaCDB .