Home
Class 9
MATHS
ABC is a triangle, right angled at B. If...

ABC is a triangle, right angled at B. If BCDE is a square on side BC and ACFG is a square on AC, prove that AD = BF.

Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    NAGEEN PRAKASHAN|Exercise Revision Exercise (short Answer Type Question)|10 Videos
  • SURFACE AREA AND VOLUME

    NAGEEN PRAKASHAN|Exercise Revision Exercise (long Answer Questions)|10 Videos

Similar Questions

Explore conceptually related problems

In the given figure, ABC is a triangle, right angled at B. If BCDE is a square on side BC and ACFG is a square on AC, prove that AD = FB.

ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segment A X_|_D E meets BC at Y. Show that: (i) DeltaM B C~=DeltaA B D (ii) a r" "(B Y X D)" "=" "2" "

/_\ABC is a right triangle, right angled at B. angleC is a given acute angle. So side BC is base, a side AB is altitude and side AC is hypotenuse for given acute angle C. The ratio (BC)/(AC) is equal to ________

ABC is a triangle right angled at B.D is a point on AC such that /_ABD=45^(@) If AC=6 and AD=2 then AB=

ABC is a right triangle right angled at C and AC = sqrt3BC . Prove that angleABC= 60^(@) .

ABC is a triangle right angled at Aand a perpendicular AD is drawn on the hypotenuse BC. What is BC.AD equal to ?

D is a point on side BC of Delta ABC such that AD=AC. Show that AB>AD

Delta ABC is a right triangle right angled at A such that AB=AC and bisector of /_C intersects the side AB at D.Prove that AC+AD=BC .