Construct a `DeltaABC` in which base `BC = 5.2 cm`, `angleABC = 50^(@)` and `AB - AC = 2 cm.`

Explanation

Steps of construction :
1. Draw `BC = 5.3 cm.`
2. Construct `anglePBC = 50^(@)` and cut `BP = 2 cm.`
3. Join `PC.`
4. Draw the perpendicular bisector of `PC` which intersect `BP` produced at `A.`
5. Join `AC.`
`therefore DeltaABC` is the required triangle.