In the adjoining figure, DE || BC . Prove that area (Delta ACD) = " area " (Delta ABE)

The medians of Delta ABC intersect at point G. Prove that: area of Delta AGB = (1)/(3) xx " area of " Delta ABC

In the adjoining figure, D is the mid-point of side AB of Delta ABC and P be any point on side BC. If CQ ||PD , then prove that: area of Delta BPQ = (1)/(2) xx " area of " Delta ABC

In the adjoining figure, BD = CE and angleADB=angleAEC=90^(@) , prove that (i) DeltaABD cong DeltaACE (ii) ABC is an isosceles triangle.

D is the mid-point of side AB of the triangle ABC.E is the mid-point of CD and F is the mid-point of AE. Prove that 8 xx " area of " (DeltaAFD) = " area of " Delta ABC

In the adjoining figure, AB=AC and BD=DC Prove that Delta ADB-=Delta ADC and hence show that (i) /_ADB-=/_ADC=90^(@) , (ii) /_BAD=/_CAD

In the adjoining figure D, E and F are the mid-points of the sides BC, CA and AB respectively of Delta ABC . Prove that: (i) square BDEF is a parallelogram (ii) area of Delta DEF = (1)/(4) xx " area of " Delta ABC (iii) area of square BDEF = (1)/(2) xx " area of " Delta ABC

In the adjoning figure, D and E are the points on the sides AB and AC respectively of Delta ABC and area of Delta BCE = " area of " Delta BCD . Prove that DE ||BC

in the adjjoining figure,AB=AC and AD=AE . Prove that 1./_ADB=/_AEC2Delta ABD~=/_ACE3.BE=DC

In the adjoining figure, ABCD is a quadrilateral in which AD ||BC . AC and BD intersect each other at point 'O'. Prove that: area of Delta COD = " area of " Delta ABO