If the product of zeroes of the polynomial `x^(2)+5x-k` is 10, then find the value of k.

Explanation

To solve the problem, we need to find the value of \( k \) given that the product of the zeroes of the polynomial \( x^2 + 5x - k \) is 10.

### Step-by-Step Solution:

1. **Identify the polynomial and its coefficients**:
The given polynomial is:
\[ x^2 + 5x - k \]
Here, we can identify the coefficients:
- \( a = 1 \) (coefficient of \( x^2 \))
- \( b = 5 \) (coefficient of \( x \))
- \( c = -k \) (constant term)

2. **Use the relationship for the product of the roots**:
For a quadratic polynomial of the form \( ax^2 + bx + c \), the product of the roots (zeroes) is given by:
\[ \text{Product of roots} = \frac{c}{a} \]
In our case:
\[ \text{Product of roots} = \frac{-k}{1} = -k \]

3. **Set up the equation**:
According to the problem, the product of the roots is equal to 10:
\[ -k = 10 \]

4. **Solve for \( k \)**:
To find \( k \), we can rearrange the equation:
\[ k = -10 \]

### Final Answer:
Thus, the value of \( k \) is:
\[ \boxed{-10} \]