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Find the distance between the parallel l...

Find the distance between the parallel lines `3x+4y-7=0` and `3x+4y+8=0`.

A

`1` units.

B

`2` units.

C

`3` units.

D

`4` units.

Text Solution

Verified by Experts

The correct Answer is:
C
Put `y=0` in `3x+4y-7=0`
`3x+0-7=0`
`implies x=(7)/(3)`
`:.` Point `((7)/(3),0)` lies on this line
Now, the length of perpendicular from `((7)/(3),0)` to the second line `3x+4y+8=0` is
`=|(3*(7)/(3)+0+8)/(sqrt(3^(2)+4^(2)))|=|(15)/(5)|=3` units.
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Knowledge Check

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