Find the equation of a line passing through the point of intersection of the lines `x+3y+1=0` and `2x-y+3=0` and parallel to the line `3x-2y+1=0`.

Explanation

To find the equation of a line passing through the point of intersection of the lines \(x + 3y + 1 = 0\) and \(2x - y + 3 = 0\) and parallel to the line \(3x - 2y + 1 = 0\), follow these steps:

### Step 1: Find the point of intersection of the two lines
To find the point of intersection, we need to solve the equations:
1. \(x + 3y + 1 = 0\) (Equation 1)
2. \(2x - y + 3 = 0\) (Equation 2)

From Equation 1, we can express \(x\) in terms of \(y\):
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