Find the equation of the line passing through (-3,5) and perpendicular to the line through the points (2,5) and (-3,6).

Explanation

Slope of a line passing through the points `(2,5)` and `(-3,6)` is
`m_(1)=(6-5)/(-3-2)=-(1)/(5)`
If slope of perpendicular line is `m_(2)` then
`m_(1)m_(2)=-1`
`implies m_(2)=-(1)/(m_(1))=5`
Now, equation of a line of slope `5` and passing through the point `(-3,5)` is
`y-5=5(x+3)`
`implies y-5=5x+15`
`implies 5x-y+20=0`