The perpendicular from the origin to the line `y=mx+c` meets it at the point `(-1,2)`. Find the values of `m` and `c`.

Explanation

Let the perpendicular drawn from `P(0,0)` to the line `y=mx+c`
meets it at `Q(-1,2)`.
`:.` Slope of `PQ`
`=(2-0)/(-1-0)=-2`
Slope of `y=mx+c` is `m`
`:. M(-2)=-1` (`:'` Both lines are perpendicular)
`implies m=(1)/(2)`
Point `(-1,2)`, lies on the straight line `y=mx+c`
`:. 2=-m+c`
`implies 2=-(1)/(2)+c` (`:' m=(1)/(2)`)
`implies c=(5)/(2)`
Therefore, `m=(1)/(2)` and `c=(5)/(2)`.