Find the equations of the lines, which cut-off intercepts on the axes whose sum and product are `1` and `-6` , respectively.

Explanation

Let equation of line be,
`(x)/(a)+(y)/(b)=1` ……..`(1)`
Given that , `a+b=1 ` and `ab=-6`
On solving,
`a=3`, `b=-2` or `a=-2`, `b=3`
`:.` From equation `(1)`, equation of line
`(x)/(3)+(y)/(-2)=1` or `(x)/(-2)+(y)/(3)=1`
`implies 2x-3y=6`or `3x-2y+6=0`