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Find the sum of the series: (2^(2)+...

Find the sum of the series:
`(2^(2)+4^(2)+6^(2)+8^(2)+ ..."to n terms")`

Text Solution

Verified by Experts

The correct Answer is:
(i) `(2)/(3)n(n+1)(2n+1)` (ii) `(1)/(3)n(4n^(2)+6n-1)`
(iii) `(1)/(3)n(n+1)(4n+5)` (iv) `(1)/(4)n(n+1)(n+2)(n+3)`
(v) `(1)/(6)n(n+1)(6n^(2)+14n+7)` (vi) `(1)/(6)n(n+1)(n+2)`
(vii) `(1)/(6)n(n+1)(2n+1)` (viii) `(1)/(2)n(n^(3)+4n^(2)+4n-1)`
N/a
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