Write the first five terms of each of the sequences in Questions 1 to 6 whose nth terms are :
`a_(n)=(2n-3)/(6)`

Explanation

To find the first five terms of the sequence defined by the nth term \( a_n = \frac{2n - 3}{6} \), we will substitute \( n \) with values from 1 to 5.

### Step-by-step Solution:

1. **Calculate \( a_1 \)**:
\[ a_1 = \frac{2(1) - 3}{6} = \frac{2 - 3}{6} = \frac{-1}{6} \]

2. **Calculate \( a_2 \)**:
\[ a_2 = \frac{2(2) - 3}{6} = \frac{4 - 3}{6} = \frac{1}{6} \]

3. **Calculate \( a_3 \)**:
\[ a_3 = \frac{2(3) - 3}{6} = \frac{6 - 3}{6} = \frac{3}{6} = \frac{1}{2} \]

4. **Calculate \( a_4 \)**:
\[ a_4 = \frac{2(4) - 3}{6} = \frac{8 - 3}{6} = \frac{5}{6} \]

5. **Calculate \( a_5 \)**:
\[ a_5 = \frac{2(5) - 3}{6} = \frac{10 - 3}{6} = \frac{7}{6} \]

### Final Result:
The first five terms of the sequence are:
\[ a_1 = -\frac{1}{6}, \quad a_2 = \frac{1}{6}, \quad a_3 = \frac{1}{2}, \quad a_4 = \frac{5}{6}, \quad a_5 = \frac{7}{6} \]