The Fibonacci sequence is defined by `1=a_(1)=a_(2)and a_(n)=a_(n-1)+a_(n-2),ngt2.`
`"Find "(a_(n+1))/(a_(n)),"for n = 1, 2, 3, 4, 5."`

Answer

N/a

Explanation

1st term of given sequence `a_(1)=1,` and 2nd term `a_(2)=1` and nth them of given sequence `a_(n)=a_(n-1)+a_(n-2)`
`"At n"=3, "third term "a_(3)=a_(3-1)+a_(3-2)=a_(2)+a_(1)=1+1=2,`
`"At n"=4, "fourth term "a_(4)=a_(4-1)+a_(4-2)=a_(4)+a_(2)=2+1=3,`
`"At n"=5, "fifth term "a_(5)=a_(5-1)+a_(5-2)=a_(4)+a_(3)=3+2=5,`
`"At n"=6, "sixth term "a_(6)=a_(6-1)+a_(6-2)=a_(6)+a_(4)=5+3=8,`
`"Then " a_(1)=1, a_(2)=1,a_(3)=2,+a_(4)=3,a_(5)=5,a_(6)=8`
`"If n=1, then" a_(2)=1, a_(3)=2,a_(4)=3,+a_(5)=5,a_(6)=8`
`"If n=2, then "(a_(n+1))/(a_(n))=(a_(2+1))/(a_(2))=a_(3)/(a_(2))=(2)/(1)=2,`
`"If n=3, then "(a_(n+1))/(a_(n))=(a_(3+1))/(a_(3))=a_(4)/(a_(3))=(2)/(3),`
`"If n=4, then "(a_(n+1))/(a_(n))=(a_(4+1))/(a_(4))=a_(5)/(a_(4))=(5)/(3),`
`"If n=5, then "(a_(n+1))/(a_(n))=(a_(5+1))/(a_(5))=a_(6)/(a_(5))=(8)/(5),`
`"Therefore, for n = 1, 2, 3, 4, 5"`
`(a_(n+1))/(a_(n))" are "1, 2,(3)/(2),(5)/(3)and(8)/(5)" respectively."`