Insert five numbers between 8 and 26 such that the resulting sequence is an A.P.

Answer

N/a

Explanation

Let required 5 numbers are `a_(1),a_(2),a_(3),a_(4)" and "a_(5).`
Then progression `8, a_(1),a_(2),a_(3),a_(4),a_(5), 26` is an A.P.
`therefore` First term of A.P.=8 and common difference will be d.
Now 7th term of progression `=a_(1)+6d`
`rArr" "26=8+6xxd`
`d=3`
`therefore" "a_(1)=8+d=8+3=11,`
`"Then, "a_(2)=a_(1)+d=11+3=14,`
`a_(3)=a_(2)+d=14+3-17,`
`a_(4)=a_(3)+d=17+3=20,`
`a_(5)=a_(4)+d=20+3=23,`
Therefore, required numbers are 11,14,17,20,23.