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Find the sum to n terms of the series, w...

Find the sum to n terms of the series, whose `n^(t h)`terms is given by : `n^2+2^n`

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The correct Answer is:
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`T_(n) = n^(2) + 2^(n)`
`rArr` `S_(n) = sum (n^(2) + 2^(n)) = sumn^(2) + sum 2^(n)`
`= (1)/(6)n(n + 1)(2n + 1) + (2 + 2^(2) + 2^(3) + … + 2^(n))`
`= (1)/(6)n(n + 1)(2n + 1) + (2(2^(n) - 1))/(2 - 1)`
`= (1)/(6)n ( n + 1) (2n + 1) + 2(2^(n) - 1)`
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