solve : `|3x-2|le1`

Answer

N/a

Explanation

We know that `|x|le a`
`rArr -a le x le a `
` :. | 3x - 2|le 1`
`rArr -1le (3x-2) le 1`
`rArr -1+2 le 3x le 1+2`
`rArr 1le 3x le 3`
`rArr (1)/(3) le xle 1`
`:. X in [(2)/(3). 1].`