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37 - (3x + 5 ) ge 9x - 8 (x - 3)...

`37 - (3x + 5 ) ge 9x - 8 (x - 3) `

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The correct Answer is:
N/a
Given inequation :
`37 - (3x + 5) ge 9x - 8 (x - 3) `
`rArr 37 - 3x - 5 ge 9x - 8x + 24`
`rArr 32 - 3x ge x + 24 `
`rArr -3x ge x - 8 `
`rArr -4 x ge -8`
`rArr x le 2`
`rArr :. Solution = ( - infty , 2]
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Knowledge Check

  • The solution set of the inequality 37-(3x+5)ge9x-8(x-3) is

    A
    `(-oo,2)`
    B
    `(-oo,-2)`
    C
    `(-oo,2]`
    D
    `(-oo,-2]`

  • Solve: (7x + 3)/(4) + ( 9x - 5)/(8) = (16 x - 3)/(16) The following steps are involved in solving the above problem. Arrange them in sequential order. (A) x = ( -5)/(30) = (-1)/(6) (B) ( 7x + 3)/(4) + ( 9x - 5)/(8) = (16 x - 3)/(16) implies (14 x + 6 + 9x - 5)/(8) = (16 x - 3)/(16) (C) (23 x + 1)/(8) = ( 16 x - 3)/(16) implies 23 x + 1= ( 16 x -3)/(2) (D) 46 x + 2 = 16 x - 3 implies 30 x =- 5

    A
    BCDA
    B
    CBDA
    C
    BCAD
    D
    BDCA

  • If log_(3) ( 3 + x) + log_(3) (8 - x) - log_(3) ( 9x - 8) = 2 - log_(3) 9, then x =

    A
    4
    B
    `-4`
    C
    `-8`
    D
    none of these

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    3x ^(5) + 9x ^(3) - 162 x

    Find x such that 3x-3x ge x +5 and (1)/(x -1) ge (1)/(8)

    Z = 3x + 5y x + y ge 2, x + 3y ge 3 x ge 0 ,y ge 0

    If 3 ( 5x - 7) - 4 ( 8x - 13) = 2 ( 9x - 11) - 17, then the value of ( 7x - 5)/(11 x - 9) is

    Solve : (7x +3)/(4) + (9x -5)/(8) = (16x-3)/(16) The following steps are involved in solving the above problem. Arrange them in sequential order (A) x = (-5)/(30) = (-1)/(6) (B) (7x + 3)/(4) + (9x -5)/(8) = (16x-3)/(16) rArr (14x + 6 + 9x -5)/(8) = (16x -3)/(16) (C) (23x + 1)/(8) = (16x -3)/(16) rArr 23x + 1 = (16x -3)/(2) (D) 46x + 2 = 16x - 3 rArr 30 x = -5

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