`3x + 2y le 12, x ge 1, y ge 2`

Answer

N/a

Explanation

First inequation : `3x + 2y le 12`
Corresponding equation : ` 3x + 2y le 12`
It cuts the X-axis at point A(4, 0) and Y-axis at point B (0, 6). At point (0, 0) from the inequation `0 le 12 (True)`
`:.` The solution of this inequation is that region of the plane divided by line AB in which (0, 0) lies.
Second inequation : `x ge 1`
Corresponding equation : `x = 1`
It is a line parallel to Y-axis and at a distance of 1 unit from it which passes thrugh the point C (1, 0).
At point (0, 0), from the inequation, `0 ge 1` (False) It solution is on right side of the line.
Third ineqution : ` yge 2`
Corresponding equation : y =2
It is a line parallel to X-axis and at a distance of 2unit from it which passes through the point, `0ge2` (False) Its solution is above the line.

The common solution of three inequation is shown by the shaded region PQR.