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6 le -3 (2x - 4) lt 12...

`6 le -3 (2x - 4) lt 12`

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The correct Answer is:
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`6 le -3 (2x - 4) lt 12`
`rArr -2 le 2x - 4 gt 4`
`rArr -4 lt 2x -4 le -2`
`rArr - 4 + 4 lt 2x le -2 + 4 `
`rArr 0 lt 2x le 2`
`rArr 0 lt x lt 1`
`:. X in (0, 1]`
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