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Find the 13^(t h)term in the expansion ...

Find the `13^(t h)`term in the expansion of `(9x-1/(3sqrt(x)))^(18),x!=0`

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The correct Answer is:
N/a
`T_(13)=T_(12+1)`
`=^(18)C_(12)(9x)^(18-12)(-(1)/(3sqrt(x)))^(12)`
`(|ul18)/(|ul12|ul6).(9^(6).x^(6))/(3^(12).x^(6))`
`(13xx14xx15xx16xx17xx18)/(18)`
`=18564.`
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