Find the middle term in the expansion of `(3x-(1)/(2x))^(16)`

Answer

N/a

Explanation

No. of terms in the expansion of `(3x-(1)/(2x))^(16) =16 +1=17 (" odd ")`
Middle term `=(17+1)/(2)` th term
=9th term
`T_(8+1)`
`=^(16)C_(8).(3x)^(16-8)(-(1)/(2x))^(8)`
`(|ul16)/(|ul8|ul8).(3^(8).x^(8))/(2^(8).x^(8))`
`(9xx10xx11xx12xx13xx14xx15xx16)/(1xx2xx3xx4xx5xx6xx7xx8)xx(3^(8))/(2^(8))`
`(12870xx6561)/(256)=(42220035)/(128).`