Find the middle term in the expansion of `(1+2x+x^(2))^(10)`

Answer

N/a

Explanation

`(1+2x+x^(2))^(10)`
`=[(1+x)^(2)]^(10)`
`=(1+x)^(20)`
No. of terms =20 +1 =21 (odd)
`:.` Middle term `=(21+1)/(2)`th term =11th term
`T_(10+1)=^(20)C_(10)(1)^(20-10).x^(10)`
`(|ul20)/(|ul10|ul10).x^(10)=184756.x^(10).`